/*
 * Before compilation and execution, understand what could be the output of the program.
 * Program demostrates that pointers does not allow arithmentic operations like multipy/division/modulo.
 * To run program replace line
 * 	j = i * 2;
 * 	with
 * 	j = (int)i * 2;
 */

#include <stdio.h>

int main()
{
	int *i, *j;

	j = i * 2;
	printf("j = %u\n", j);

	return 0;
}
